Someone mentioned the even and odd distribution and how it would make sense for J and K to be odd. I do think it's a bit odd that 8 of the 13 ranks are even (2, 4, 6, 8, 10, J, Q, K) while only 5 are odd (3, 5, 7, 9, A). I think one solution to even things up is to consider A as 1, in which case it is straightforward to consider it odd. Thus the split would be (2, 4, 6, 8, 10, Q) for 6 even ranks, and (A, 3, 5, 7, 9, J, K) for 7 odd ranks. To have an exact split, A could be considered both even and odd (as 1/11 and 14), just like it is considered both a high and low number.
While it would be fun to allow Aces to be both even and odd, there is another goal in mind, that is for evens/odds to be significantly different from the red/black distribution.
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While it would be fun to allow Aces to be both even and odd, there is another goal in mind, that is for evens/odds to be significantly different from the red/black distribution.