PongOut
ni AgafInc
PongOut
Mga tag para sa PongOut
Deskripsyon
PongOut combines two classic games to make one new game. Using just the mouse you will have to control both a Pong and Breakout game... at the same time!
Paano Maglaro
Left and Right movement controls Breakout and Up and Down movement controls Pong. Press P to pause and M to mute. There will be a small delay when coming back from a pause, this is an intentional delay to prevent cheaters from taking advantage of this function.
FAQ
Ano ang PongOut?
Ang PongOut ay isang browser-based arcade game na ginawa ng AgafInc na pinagsasama ang mga elemento ng klasikong Pong at Breakout games.
Paano nilalaro ang PongOut?
Sa PongOut, kinokontrol mo ang dalawang paddle nang sabay—isa para sa Pong sa itaas at isa para sa Breakout sa ibaba—gamit ang iyong keyboard para mapanatili ang bola sa laro sa parehong board.
Sino ang gumawa ng PongOut?
Ang PongOut ay nilikha ng AgafInc at libre itong malalaro sa Kongregate.
Ano ang nagpapakaiba sa PongOut kumpara sa ibang arcade games?
Namumukod-tangi ang PongOut dahil pinagsasama nito ang dalawang klasikong arcade style, hinahamon ang mga manlalaro na maglaro ng Pong at Breakout nang sabay para sa kakaiba at mabilisang gameplay.
Single player ba o multiplayer ang PongOut?
Ang PongOut ay isang single-player arcade game kung saan isang manlalaro ang kumokontrol sa parehong paddle para makuha ang pinakamataas na score.
Mga Komento
blehmeh98
Jul. 26, 2015
also . . . What if scoring one goal in pong got you a life?
duncanbeevers
Feb. 26, 2008
Could use a bit better hit detection. Especially since I find I have to rush to save the ball almost all the time, it's frustrating when it gets stuck inside my paddle.
alexander720151
Jun. 03, 2018
this is impossible
Archaris
Jan. 16, 2009
nice idea for a combination of two classics but for me, it's not fun because too much attention is split up between sides. maybe you could have put the blocks in the middle and had 4 pong paddles around the outside instead.
sokob4n
Jul. 10, 2018
perhaps it is possible if we divide the speed by 2...