
metadata



metadata



metadata
i don’t remember how to do that



metadata
Okay what I came out with is some crazy clusterfuck.



metadata
Just an elegant ruse to trick us into doing his homework for him
maybe



metadata
~~lets give him fake answers~~ try 54r3



metadata



metadata
You know that triangle? The answer to that question is : The sum of the angles in that triangle is 679o



metadata
> *Originally posted by **[VoodooCoffeeGuy](/forums/2/topics/315186?page=1#posts6650023):***
>
> You know that triangle? The answer to that question is : The sum of the angles in that triangle is 679o
Could actually be possible (I will have to consult my references to verify) in spherical geometry (yes, there exist forms of noneuclidean geometry – triangles don’t have to add up to 180 degrees, straight lines are called geodesics and any given line may have more than 1 parallel line through any given point outside it). In spherical geometry, angles are outwardly bloated, so an angle of euclidean space as projected into the manifold of noneuclidean space would have distinctly different properties akin to that between footage of a video recording and cartoon animation.



metadata
> *Originally posted by **[cllazyman](/forums/2/topics/315186?page=1#posts6649924):***
>
> Find the eighth term of (3a5b)11
> First person to answer correctly gets an internet cookie.
![](http://latex.codecogs.com/gif.latex?2088281250*a^4*b^7)
Cookie please.



metadata



metadata
> *Originally posted by **[simeng](/forums/2/topics/315186?page=1#posts6650070):***
> > *Originally posted by **[VoodooCoffeeGuy](/forums/2/topics/315186?page=1#posts6650023):***
> >
> > You know that triangle? The answer to that question is : The sum of the angles in that triangle is 679o
>
> Could actually be possible (I will have to consult my references to verify) in spherical geometry (yes, there exist forms of noneuclidean geometry – triangles don’t have to add up to 180 degrees, straight lines are called geodesics and any given line may have more than 1 parallel line through any given point outside it). In spherical geometry, angles are outwardly bloated, so an angle of euclidean space as projected into the manifold of noneuclidean space would have distinctly different properties akin to that between footage of a video recording and cartoon animation.
You actually don’t know what the hell you’re doing, just making a pointless wall of text (like usual)



metadata
> *Originally posted by **[cllazyman](/forums/2/topics/315186?page=1#posts6650060):***
>
> I give you guys 3 days to figure this out. If you can’t, then I will call you all idiots.
> Aldir was the closest to the answer. Also, this is algebra.
Aldir was the furthest actually since the answer is negative 2 billion and Aldir said 1 billion. He was 3 billion off. Lol



metadata
> *Originally posted by **[Dante\_Dreiman](/forums/2/topics/315186?page=1#posts6650243):***
> > *Originally posted by **[cllazyman](/forums/2/topics/315186?page=1#posts6650060):***
> >
> > I give you guys 3 days to figure this out. If you can’t, then I will call you all idiots.
> > Aldir was the closest to the answer. Also, this is algebra.
>
> Aldir was the furthest actually since the answer is negative 2 billion and Aldir said 1 billion. He was 3 billion off. Lol
birrrrion\*



metadata
> *Originally posted by **[Aldir](/forums/2/topics/315186?page=1#posts6650257):***
> > *Originally posted by **[Dante\_Dreiman](/forums/2/topics/315186?page=1#posts6650243):***
> > > *Originally posted by **[cllazyman](/forums/2/topics/315186?page=1#posts6650060):***
> > >
> > > I give you guys 3 days to figure this out. If you can’t, then I will call you all idiots.
> > > Aldir was the closest to the answer. Also, this is algebra.
> >
> > Aldir was the furthest actually since the answer is negative 2 billion and Aldir said 1 billion. He was 3 billion off. Lol
>
> birrrrion\*
/facepalm
Aldir was the furthest actually since the answer is negative 2 birrrrion and Aldir said 1 birrrrion. He was 3 birrrrion off. Lol
There, better?



metadata



metadata
> *Originally posted by **[cllazyman](/forums/2/topics/315186?page=1#posts6650060):***
>
> I give you guys 3 days to figure this out. If you can’t, then I will call you all idiots.
> Aldir was the closest to the answer. Also, this is algebra.
How about i give you 4 days to solve this **without** using a calculator?
![](http://latex.codecogs.com/gif.latex?\sqrt{4,444,444,444%20%2088,888})



metadata
> *Originally posted by **[Dante\_Dreiman](/forums/2/topics/315186?page=1#posts6650281):***
> > *Originally posted by **[cllazyman](/forums/2/topics/315186?page=1#posts6650060):***
> >
> > I give you guys 3 days to figure this out. If you can’t, then I will call you all idiots.
> > Aldir was the closest to the answer. Also, this is algebra.
>
> How about i give you 4 days to solve this **without** using a calculator?
> ![](http://latex.codecogs.com/gif.latex?\sqrt{4,444,444,444%20%2088,888})That’s a simple Newton’s Approximation.



metadata
> *Originally posted by **[BobTehLoner](/forums/2/topics/315186?page=1#posts6650240):***
> > *Originally posted by **[simeng](/forums/2/topics/315186?page=1#posts6650070):***
> > > *Originally posted by **[VoodooCoffeeGuy](/forums/2/topics/315186?page=1#posts6650023):***
> > >
> > > You know that triangle? The answer to that question is : The sum of the angles in that triangle is 679o
> >
> > Could actually be possible (I will have to consult my references to verify) in spherical geometry (yes, there exist forms of noneuclidean geometry – triangles don’t have to add up to 180 degrees, straight lines are called geodesics and any given line may have more than 1 parallel line through any given point outside it). In spherical geometry, angles are outwardly bloated, so an angle of euclidean space as projected into the manifold of noneuclidean space would have distinctly different properties akin to that between footage of a video recording and cartoon animation.
>
> You actually don’t know what the hell you’re doing, just making a pointless wall of text (like usual)
I do understand what I am talking about. However, you obviously don’t, since you are expressively denying the validity of truth and thereby holding it in contempt. Do not condemn me for good service; whereas I am in honorable comprehension, you renege on the most basic of preliminary assumptions.
EDIT: perhaps I wasn’t being clear enough, given your status. i’ll cut to the chase, GTFO. you have really begun irritating me with your ad hominem arguments.



metadata
> *Originally posted by **[LukeMann](/forums/2/topics/315186?page=1#posts6650496):***
> > *Originally posted by **[Dante\_Dreiman](/forums/2/topics/315186?page=1#posts6650281):***
> > > *Originally posted by **[cllazyman](/forums/2/topics/315186?page=1#posts6650060):***
> > >
> > > I give you guys 3 days to figure this out. If you can’t, then I will call you all idiots.
> > > Aldir was the closest to the answer. Also, this is algebra.
> >
> > How about i give you 4 days to solve this **without** using a calculator?
> > ![](http://latex.codecogs.com/gif.latex?\sqrt{4,444,444,444%20%2088,888})That’s a simple Newton’s Approximation.
No, not an approximation, i want the **exact** solution. And the exact solution is a five digit natural number, i think i said enough.
> *Originally posted by **[cllazyman](/forums/2/topics/315186?page=1#posts6650680):***
>
> I’ll solve it once you solve this:
> √25/0
> No words allowed.
Lol, you can’t divide by zero. Do you mean the limit of ![](http://latex.codecogs.com/gif.latex?\sqrt{25}/x) for x going to 0, x real number? That would be plus infinity when x goes to zero with x\>0 and minus infinity when x goes to zero with x\<0. Of course we still have the square root of 25 which is 5i (or 5j if you are an engineering or physics student) which would make infinity complex. Now, why don’t you sit down and solve my problem which is middle school level maths and not calculus? I am already 2 problems up compared to you.
Edit:
Of course you could also mean the limit as z→0 where z is a complex number of 5i/z. Of course that limit doesn’t exist. doesn’t exist.
5i/z = 5i/(x+yi) = 5y/(x^2+y^2) + 5xi/(x^2+y^2), where (x,y)→ (0,0). Those two functions don’t have a limit as (x,y)→(0,0). Therefore 5i/z doesn’t have one either. Q.E.D.



metadata
> No, not an approximation, i want the exact solution. And the exact solution is a five digit natural number, i think i said enough.
You can get exact values for rational roots with Newton’s Approximation, though.
