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Thanks to Ikara for finding two bugs in my Metatron.. here's the fixed version:
?lvl=31&code=c13:9f0;c6:8f3;c6:9f3;c6:10f3;c7:9f1;c13:7f3;c13:8f3;c6:11f3;c13:10f2;c14:8f2;c14:9f1;c14:10f1;q15:11f0;i16:9f5;c16:10f3;i17:8f2;q17:11f6;c18:8f0;c18:9f1;c18:10f1;c17:13f0;c16:13f0;c15:13f0;c16:12f3;c6:12f3;c6:13f2;c7:13f2;c8:13f2;q9:13f6;b9:12f2;c10:13f2;q7:11f2;y7:12f1;p8:11f0;r8:12f1;g8:8f3;y8:9f2;b8:10f3;q9:8f1;c9:9f3;c9:10f3;c9:11f0;c10:9f2;c10:10f0;c11:9f1;c11:10f0;c10:7f3;p10:8f3;r11:7f0;q11:8f5;b12:7f2;g12:8f1;b9:7f2;g6:6f3;c6:7f3;q7:6f1;q7:7f2;c8:6f1;c8:7f1;c8:5f1;c12:9f3;c12:10f0;r6:3f3;p6:4f2;b6:5f1;q7:4f4;b6:1f2;y6:2f2;p7:1f3;q7:2f5;r8:1f0;c7:10f1;c16:5f0;c17:5f0;c18:5f0;g14:3f3;b15:2f2;q15:3f1;c16:2f3;p16:3f3;c16:4f2;r17:2f0;
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q17:3f5;c17:4f1;g18:3f3;r18:4f3;c13:2f1;c13:1f2;c14:1f2;c15:1f2;c16:1f3;g7:3f1;p16:11f7;b18:11f1;b17:12f3;r15:12f3;y17:10f1;r17:9f1;b15:10f1;r14:11f1;b16:6f2;p17:6f3;r18:6f0;q17:7f1;g16:7f3;y18:7f0;c16:8f3;c15:8f2;q14:13f4;c14:12f3;y10:11f2;r10:12f2;q11:11f3;p11:12f1;b12:12f0;g12:11f2;c13:13f0;g7:5f1;c9:2f2;c10:2f2;c15:5f3;c15:6f3;c15:7f0;c14:7f0;b14:4f2;c15:4f3;g9:5f3;c9:6f2;b10:4f2;q10:5f1;c10:6f3;c11:4f3;p11:5f3;c11:6f2;r12:4f0;q12:5f5;c12:6f1;c13:4f1;g13:5f1;g12:3f0;c13:3f1;c8:4f1;g12:2f3;c8:3f2;c9:3f2;c10:3f2;g7:8f1;c11:2f3;c11:3f3;g8:2f2;q13:11f4;c15:9f2;r11:13f1;
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@Herennious: it does not work if the difference between the number of reds and the number of blues is even (1 blue - 3 red would pass).
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My solution for andriods:
?lvl=17&code=c12:10f3;g10:3f3;p10:4f0;g10:5f3;p10:6f3;c10:7f3;q10:8f3;g11:4f0;g11:6f0;q11:8f1;p12:4f3;c12:5f3;c12:6f3;c12:7f3;c12:8f3;c12:9f3;c11:9f2;c10:9f2;
It works by first checking if the first one is blue, if so, add a green counter, then count blues and add greens until red is reached, discarding when red can't be found, then count reds by adding greens, discarding when a blue is found, when done it checks the number of greens. If this number is even the robot is valid, else it is invalid.
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@Taolas: For current version of Androids (accept X blues, followed by same number of reds), I've got 12 parts and 0:37. Robomecha (put last color at front) is 19 parts, 0:26. I think both of those are about as good as I can get.
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Well, Androids, Robo Children and Teachers have gotten changed around. And to think, I was working on Teachers too. Oh well, the game is still in progress I suppose. I hope there won't be many more puzzle changes, but I'm not happy with Random Tests. There are many different elements for a universal solution to function, and Random Tests may not test all of them. This will likely compromise the difficulty of these puzzles.
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I have a pretty elegant solution for Androids that uses recursion. It is not optimal (25 parts); I have a dirtier but faster solution in 17 that only works for finite sequences, but it is far less interesting in my opinion. Basically, it outputs the same string with one less blue and one less red, then tests if the final two-dot string contains exactly one blue and one red.
?lvl=17&code=c9:7f1;c9:8f1;c9:9f1;b10:7f2;q10:9f0;c10:10f2;c11:6f3;p11:7f3;g11:9f0;c11:10f2;p12:6f3;i12:7f7;i12:8f6;i12:9f1;c12:10f3;c13:7f3;p13:8f3;q13:9f1;r14:8f0;c9:6f1;c10:5f2;c11:5f2;c12:5f3;g12:4f3;c9:5f2;
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My solution to judiciary: ?lvl=20&code=b11:1f3;p11:2f0;r11:3f1;g12:2f0;q7:3f0;c7:4f3;b8:2f3;p8:3f0;r8:4f1;c9:3f0;b6:5f3;g6:6f3;c6:7f2;p7:5f3;i7:7f7;r8:5f3;g8:6f3;c8:7f2;c11:4f0;c12:4f0;c13:4f0;c14:4f0;c16:4f0;c15:4f0;c10:4f0;c9:4f1;c7:1f2;c8:1f2;c9:1f3;c9:7f2;c10:7f2;c11:7f2;c12:7f2;r13:6f3;c13:7f2;b13:8f1;g14:5f2;q14:6f4;p14:7f2;q14:8f0;g14:9f2;r15:5f2;b15:9f2;c16:5f1;c16:6f1;c16:7f1;c16:8f1;c16:9f1;y9:2f3;c7:2f1;g10:2f0;c7:6f3;q9:11f3;y10:9f0;b10:10f2;g10:11f2;b10:12f2;y10:13f0;q11:9f5;p11:10f5;p11:11f2;p11:12f3;q11:13f3;r12:10f0;c12:11f2;r12:12f0;c7:8f3;c13:11f3;c13:12f3;c13:13f0;p9:9f0;p9:13f0;c9:12f0;c9:10f0;c6:10f3;c6:11f2;c6:12f1;r7:10f3;p7:11f2;b7:12f1;c8:11f2;c8:10f1;c8:9f0;c7:9f0;c6:9f3;c8:12f3;c8:13f0;c7:13f0;c6:13f1;
Unlike other people's solution to judiciary that I've seen, I don't reverse the second halfo the string. I don't see why that is useful? I do place marker at the mid-point and end of the string, then check that the two halves are identical.
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to compliment FreelancerMax's RoboMecha solution for few parts, I offer one with better time: 0:31 50 parts: ?lvl=28&code=c12:11f3;b8:9f2;c9:4f2;g9:5f1;r9:6f3;q9:7f4;c9:8f3;q9:9f3;c9:10f2;i10:4f7;p10:5f7;b10:6f3;r10:8f1;b10:9f1;c10:10f2;c11:4f2;y11:5f0;c11:10f2;i12:4f5;p12:5f3;c12:6f3;c12:10f3;g13:5f2;c13:10f0;p14:5f7;r14:6f3;c14:7f2;b14:8f1;r14:9f1;c14:10f0;y15:5f1;b15:6f3;q15:7f6;c15:8f3;q15:9f3;c15:10f0;r16:9f0;i12:3f1;c13:4f2;c15:4f1;c15:3f0;c14:3f0;c13:3f0;c11:3f0;c10:3f3;c10:7f0;c12:7f3;c12:8f3;c12:9f3;c14:4f3;
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Addicting, simply addicting :)
Btw, is it just me or were there a few objective-changes? the former android-objective is now in the robo-children-lvl... Anyways, my solution with fewest parts that should be able to handle any non-infinite pattern... worked long enough on it :)
?lvl=18&code=c12:3f3;p12:4f3;p11:4f3;p13:4f3;c10:3f2;c11:3f2;c9:4f1;c9:5f1;c9:6f1;c9:3f2;c13:3f0;c14:3f0;c15:3f0;c15:4f1;c15:5f1;c15:6f1;q12:6f3;q11:6f3;q13:6f3;r14:6f2;c12:7f3;c12:8f3;c12:9f3;c12:10f3;c12:11f3;g14:4f1;y10:4f1;b10:6f0;c12:5f3;
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I was having trouble until I Realized that if I put a green stamp at the start I can make the red/blue choice loop until the end, very useful for roboplanes and roborockets. Excellent game, good to see more games a similar genre to codex of alchemical engineering, very challenging and fun 5/5.
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Soldiers!
?lvl=12&code=c12:4f3;c12:5f3;c12:6f3;c12:7f3;r12:8f3;r12:9f3;r12:10f3;
pretty simple if you look up binary mutliplication
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@Bensci54: Your androids solution is flawed, it fails of RRB. Just because it passes the test doesn't make it a good solution. You pass through sheer luck. :)
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That is my super-easy roboplanes solution. BTW, most people's solutions get cut off in the post. why can't I see the whole solution? The one I just posted barely fits. I didn't write anything before it because i assumed it would get cut off if I did... =/
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@Felix: Your solution fails on RRB. (It might pass on all the puzzle entries, I didn't test - but it's a flawed solution.). Really, it fails on anything that should be rejected that ends with a single changed-color.
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@NeoKefka *laugh* (Though I should point out that many of the languages you're required to accept in this game aren't regular, such as `an equal number of reds and blues in any order'. The ability to write to the tape makes the machines more powerful than finite state machines/regular expressions.)
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@Lylat: I rejected 260 correctly, and it accepted it, so I'm not sure what happened with yours. Perhaps it's a bug. A natural power of 4 will consist of a single blue followed by an even number of reds.
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Level 16:
Accept: Natural powers of 4.
Why does it tell me to accept 260, I know it is 4^3+4^1=256+4=260, but the number itself is not a natural power of 4, so would be better to somehow rephrase the definition
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Convert to base 4 level.
?ctm=Base_4;Convert_binary_number_to_base_4._RBYG->0123;b:b|br:y|brr:br|brbbr:byy|bbrrbbrbrrrrbbbrrbb:bybybrrg|rrbbrrbbrrbb:grgrg|bbrbb:byg|bbbrrbrr:gybr;13;3;1;
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This is the greatest educational game ever made. I actually forwarded a link to my Algorithms professor. Turing machines are on the final; this is a great study aid.
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Robomecha 27 parts 0:40 ?lvl=28&code=y12:3f3;q12:11f3;c11:11f2;c12:7f3;c12:8f3;c12:9f3;c12:10f3;c12:5f3;p12:6f3;c12:4f3;c10:4f2;b11:4f2;g11:5f1;c13:4f0;r14:4f0;q14:5f1;c14:6f1;c15:4f0;g15:5f1;c13:11f0;b11:7f2;i13:6f7;c13:5f3;r13:7f0;q11:6f0;c10:6f1;c10:5f1;
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Androids 22 parts 0:37 ?lvl=17&code=b14:5f2;y15:4f3;p15:5f3;p15:6f3;c15:9f3;c16:5f3;r16:6f0;c12:4f2;c13:4f2;c14:4f2;c15:10f3;c15:11f0;c14:11f0;p9:8f3;p10:8f3;p11:8f3;p12:8f3;p13:8f3;p14:8f3;p15:8f3;c13:11f0;q15:7f2;
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?lvl=31&code=c13:9f0;c6:8f3;c6:9f3;c6:10f3;c7:9f1;c13:7f3;c13:8f3;c6:11f3;c13:10f2;c14:8f2;c14:9f1;c14:10f1;q15:11f0;c16:9f3;c16:10f3;i17:8f2;q17:11f6;c18:8f0;c18:9f1;c18:10f1;c17:13f0;c16:13f0;c15:13f0;c16:12f3;c6:12f3;c6:13f2;c7:13f2;c8:13f2;q9:13f6;b9:12f2;c10:13f2;c11:13f1;q7:11f2;y7:12f1;p8:11f0;r8:12f1;g8:8f3;y8:9f2;b8:10f3;q9:8f1;c9:9f3;c9:10f3;c9:11f0;c10:9f2;c10:10f0;c11:9f1;c11:10f0;c10:7f3;p10:8f3;r11:7f0;q11:8f5;b12:7f2;g12:8f1;b9:7f2;g6:6f3;c6:7f3;q7:6f1;q7:7f2;c8:6f1;c8:7f1;c8:5f1;c12:9f3;c12:10f0;r6:3f3;p6:4f2;b6:5f1;q7:4f4;b6:1f2;y6:2f2;p7:1f3;q7:2f5;r8:1f0;c7:10f1;c16:5f0;c17:5f0;c18:5f0;g14:3f3;b15:2f2;q15:3f1;c16:2f3;p16:3f3;c16:4f2;r17:2f0;q17:3f5;
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c17:4f1;g18:3f3;r18:4f3;c13:2f1;c13:1f2;c14:1f2;c15:1f2;c16:1f3;g7:3f1;p16:11f7;b18:11f1;b17:12f3;r15:12f3;y17:10f1;r17:9f1;r15:9f1;b15:10f1;r14:11f1;b16:6f2;p17:6f3;r18:6f0;q17:7f1;g16:7f3;y18:7f0;c16:8f3;c15:8f2;q14:13f4;c14:12f3;y10:11f2;r10:12f2;q11:11f3;p11:12f1;b12:12f0;g12:11f2;c13:13f0;g7:5f1;c9:2f2;c10:2f2;c15:5f3;c15:6f3;c15:7f0;c14:7f0;b14:4f2;c15:4f3;g9:5f3;c9:6f2;b10:4f2;q10:5f1;c10:6f3;c11:4f3;p11:5f3;c11:6f2;r12:4f0;q12:5f5;c12:6f1;c13:4f1;g13:5f1;g12:3f0;c13:3f1;c8:4f1;g12:2f3;c8:3f2;c9:3f2;c10:3f2;g7:8f1;c11:2f3;c11:3f3;g8:2f2;q13:11f4;
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Metatron. Ultimately the hardest part was fitting everything into the play-area (might wanna up the size to the max). The algorithm used is as follows: Split the string into A, B and C by greens (C starts out as null). Next merge A and B into C one at a time adding as you go (1 + 1 = Yellow - middle and top right). Check to see if both A and B are empty (requires regeneration - top left). If the head is yellow replace with 10. Expand string yellows using 1X -> X0 and 0X -> 10 (Bottom right). Once the string is out of yellows, you're done!
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@Azgara: In Androids as it stands now, BBRRBR would be a pattern to reject, but would be acceptable in Robo-Children.
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Really love this game! Small error though, how am I supposed to build a machine of five parts, if the birdway from start to stop is seven squares? This goes for a couple of the levels, for an instance the "multiply by eight"-level. You should also be able to see which ones you've "mastered" by building with minimal material from the "map". Great game anyway!
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@PleasingFungus: I believe there should be more tests. Of course, longer testing would become boring to the player, so here's my suggestion:
use six pre-made tests that have been specifically chosen to target common errors (for example, the null string in most of the levels; odd and even strings, and so on), then run a dozen tests in the background (without displaying them, which would take far too much time) and only display a test if it fails in order to aid debugging.
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another thing, you changed the androids level and moved it to the "children" level? but i don't understand the difference :s (androids: some number of blue then the same number of red, children: equal number of blue and red in any order) ??
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ok listen, there should be a switch to select random/prefixed tests because my machine was NOT working (androids level) and after the random tests were embodied it was working, not because it was correct but because the tests came that way. I liked it better when it was harder.
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Oh, and kudos for using part of one of Shostakovich's symphonies (I can't, for the life of me, remember whiche on it is) as the music. The loop gets a bit annoying after a bit, as do all loops, but it's a very cool segment to have chosen.
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A robokitties solve:
lvl=6&code=p12:5f3;c12:4f3;c11:4f2;c11:8f2;p12:8f3;c12:9f3;c12:10f3;p11:5f4;c11:6f3;c13:8f1;c13:7f1;c13:6f1;c13:5f0;c11:7f3;
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As for random generated strings, I think they're necessary, as long as there are still pre-made tests as is the case at the moment (three pre-made tests, three random ones).
Random tests are here to avoid specific designs that would only work for the pre-made tests, not the opposite. Pre-made tests alone cannot check every possible permutation; I believe the point of the game is to *solve* the problem, which means designing a solution that always works, regardless of the input. So if your builds worked before the random tests, and don't work anymore, then there is a problem with your design, not with the test.
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Bart0vds, your solution is incorrect, in only works for the specific test strings of the level. It will _reject any valid_ string with an even number of blue bits, and _accept any invalid_ string that end with an odd number of red bits. It runs pretty fast, though (55secs).
Here's my own solution for Android (1min05, 25 parts):
?lvl=17&code=c9:7f1;c9:8f1;c9:9f1;b10:7f2;q10:9f0;c10:10f2;c11:6f3;p11:7f3;g11:9f0;c11:10f2;p12:6f3;i12:7f7;i12:8f6;i12:9f1;c12:10f3;c13:7f3;p13:8f3;q13:9f1;r14:8f0;c9:6f1;c10:5f2;c11:5f2;c12:5f3;g12:4f3;c9:5f2;
I like the game, and particularly the fact you can revisit your designs to improve them, and share solutions with other players. This is pretty stimulating, and this may be the most clever game I've ever played.
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my very weird solution to lvl 17, androids:
?lvl=17&code=c10:11f2;c11:11f2;c10:7f2;p10:8f0;p10:9f3;c11:7f2;c11:8f0;c12:7f2;c12:8f0;c12:9f1;c11:9f2;q10:10f3;c9:8f1;q13:6f2;c13:7f3;q13:8f3;c13:11f0;c14:6f3;c14:7f3;c14:8f3;c14:9f3;c14:10f3;c14:11f0;y10:5f2;c11:4f3;p11:5f3;q11:6f2;c12:4f0;r12:5f0;c12:6f2;c9:7f2;
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I love this game, although in the later levels I cheated by having a simple layout and restarting the run over and over until I was lucky enough to be given a random combination that happened to work with what I had. That's how I solved Seraphim, anyway. Ideally this kind of cheating shouldn't work at all...
Before they got impossible, I did love the puzzles, though. I loved that I didn't have to be physically looking at the board to figure out a puzzle, I could walk around town thinking over possible strategies until something fit into place. Not many games can be played in absentia like this.
I'd like to see more sets of levels, though. And maybe the option of an infinite playfield for us who are incapable of making concise machinery...
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my solution for android, basically a parity check:
?lvl=17&code=c12:4f3;c8:6f3;c8:7f2;c8:8f1;g9:6f0;c9:7f2;y9:8f0;c10:5f3;i10:6f1;c10:7f2;i10:8f0;c10:9f1;i11:5f2;p11:6f1;p11:7f2;p11:8f3;i11:9f6;c12:5f0;c12:6f1;c12:8f3;c12:9f0;q14:7f2;q14:6f1;q14:8f3;c12:7f2;c13:7f2;c15:6f1;c15:5f0;i14:5f2;c13:5f3;c13:6f3;c15:8f3;c15:9f0;i14:9f6;c13:9f1;c13:8f1;c15:7f2;c16:7f3;c16:8f3;c16:10f3;c16:9f3;c16:11f0;c15:11f0;c14:11f0;c13:11f0;