I really like that this game leaves no guesswork, as was the case in the good old Windows classic. However, like two others here, I can't figure out the logic reasoning for the last six tiles in level 68 (snake that narrows). Counting from the narrow end of the snake, that is tile 1,2,3,4,8 and 9. According to the hearts, either tiles 2 and 7 or tiles 5 and 10 are lonely mines.
The only possible far-fetched reasoning I could see, is that assuming 5 and 10 were the lonely mines, we would need more information from opening of tile 4 and 9 in order to determine if 1-3 contained zero, two or three mines. While assuming the case of 2 and 7 being lonely mines, we would need no further information to determine the rest of the tiles. So considering the idea that this game is not to be based on guesswork, choosing 2 and 7 as lonely mines makes sense in a way, as it would guarantee no more guessing.
Ok - for level 68 (the snake level) it sounds like most are getting to the last 10 tiles. So from there: there is a 2-heart looking along 3-?'s, which must contain 1 lonely mine. 2 of these 3 '?' tiles can be ruled out by already satisfied hearts ... edit: I was wrong, it wasn't solvable
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 "Gib Fest Multiplayer"){kind=icon}
Ok - for level 68 (the snake level) it sounds like most are getting to the last 10 tiles. So from there: there is a 2-heart looking along 3-?'s, which must contain 1 lonely mine. 2 of these 3 '?' tiles can be ruled out by already satisfied hearts ... edit: I was wrong, it wasn't solvable